| User: editor -- 2011-07-28 << 826 828 >> |
| Hits: 4516 |
| Type: Text file parser |
| Search all Text file parser examples |
| Description: |
| How to extract all lines with specified date range from text file? There is a date with format YYYY-MM-DD at the end of each line, how to extract all lines that has date range from 2010-08-01 to 2010-09-30? |
| Input Sample: |
| ......... 2010-08-05 ............. 2011-04-12 .......... 2006-11-18 ........... 2010-09-13 ............. 2010-06-04 |
| Output Sample: |
| ......... 2010-08-05 ........... 2010-09-13 |
| Answer: |
| Hint: You need to Download and install "Replace Pioneer" on windows platform to finish following steps. |
| 1. ctrl-o open source text file 2. ctrl-h open 'replace' dialog * set 'replace unit' to 'Line' * set 'replace with pattern' to: * uncheck "print unmatched unit" option * set 'If' to: 3. click "Replace", done. 4. ctrl-s save to file. Note: (1) Above operation means extract all lines if the last word of the line within 2010-08-01 and 2010-09-31 words($match,-1) means the last word of the line ge means "greater or equal to" le means "less or equal to" (2) You need to make date conversion if date is not format of YYYY-MM-DD |
Screenshot 1: Replace_Window |
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| Keywords: |
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