| User: editor -- 2011-07-18 << 821 823 >> |
| Hits: 2320 |
| Type: Text file parser |
| Search all Text file parser examples |
| Description: |
| How to extract all records that contains specified field values? Given a file will many records, and a name list, how to extract all the records that contain these names? |
| Input Sample: |
| Records.txt name1 33 F name2 25 M name3 19 F name4 9 M ... Namelist: name1 name3 |
| Output Sample: |
| name1 33 F name3 19 F ... |
| Answer: |
| Hint: You need to Download and install "Replace Pioneer" on windows platform to finish following steps. |
| 1. ctrl-o open record.txt 2. ctrl-h open 'replace' dialog * set 'replace unit' to 'Line' * set 'search for pattern' to nothing * set 'replace with pattern' to: * set 'if' to: * uncheck 'print unmatched unit' option 3. click 'replace', done. Note: you can change the list of 'name1', 'name3' in step2 base on your own need. |
Screenshot 1: Replace_Window |
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Check Demo of Text file parser |
| Keywords: |
| records given give field grep record contains names values unmatched extract field if contains change file names replace pattern with nothing replace file names file names how to replace many file name extract file name |