| User: Aaron -- 2013-12-09 << 1155 1157 >> |
| Hits: 3125 |
| Type: Text file parser |
| Search all Text file parser examples |
| Description: |
| Variation of script 560. How to remove all the lines that do not contain any of words in a list based on percentages? |
| Input Sample: |
| word_list.txt word1|word2|word3 Keep only 50% of lines with word1 and all occurrences of word2 and word3 input.txt .....word1...... ............... ....word1........ ..word2........... ................. ............ ..word3........... |
| Output Sample: |
| Output Sample: (50% of lines with word1 remain) .....word1...... ....word2........ ..word3........... |
| Answer: |
| Hint: You need to Download and install "Replace Pioneer" on windows platform to finish following steps. |
| 1. ctrl-o open 'text' file 2. ctrl-h open 'replace' dialogue * set 'replace with pattern' to: * click 'advanced' tab set 'run following for each matched unit' to: 3. click 'replace', done. Note: you can adjust 0.5 to other values. |
Screenshot 1: Replace_Window |
Screenshot 2: Replace_Advanced_Window |